If A is the center of the circle, then which statement explains how segment EF is related to segment GF? Circle A with inscribed triangle EFG; point D is on segment EF, point H is on segment GF, segments DA and HA are congruent, and angles EDA and GHA are right angles. A. segment EF ≅ segment GF because both segments are perpendicular to radii of circle A. B. segment EF ≅ segment GF because both segments are the same distance from the center of circle A. C. segment EF ≅ segment GF because the inscribed angles that create the segments are congruent. D. segment EF ≅ segment GF because the tangents that create the segments share a common endpoint.

Answer:segment EF ≅ segment GF because both segments are the same distance from the center of circle A ⇒ answer BStep-by-step explanation:* Lets revise some facts in the circle- The perpendicular segment from the center of the circle to a chord  bisects it- A segment from the center of a circle to the midpoint of a cord is  perpendicular to it- Congruent chords in a circle are equidistant from the center of the circle,  that means the perpendicular distances from the center of the circle  to the chords are equal- If two chords in a circle are equidistant from the center of the circle  ( the perpendicular distances from the center of the circle to the   chords are equal) , then they are congruent* Lets solve the problem ∵ ∠EDA is right angle∵ AD ⊥ FE∵ ∠GHA is right angle ∵ AH ⊥ FG∵ AD = AH∵ EF and GF are chords in the circle A∴ The chords EF and GF are equidistant from the center of the circle A- By using the bold fact above∴ EF ≅ GF* segment EF ≅ segment GF because both segments are the same  distance from the center of circle A